Index

SchoolNotes

  1. CS225
    1. Introduction
    2. Lesson 1
    3. Lesson 2
    4. Lesson 3
    5. Lesson 4
  2. CS251
    1. The Beginning
  3. CS180
    1. Introduction
    2. Midterm Revision
    3. Finals Revision
    4. CS251
    5. Memory
    6. ELF Format
    7. History of Computers
    8. Stuff to Research
    9. Quiz To-Do
    10. OS Architectures
    11. Week 3
    12. Week 4
    13. Week 5
    14. Week 6 (Threads)
    15. Week 7 (Scheduling)
    16. Week 8 (Thread Scheduling)
    17. Week 9 (Memory Management)

OLD SHIT

  1. CS225 (OLD ONE IGNORE THIS)
    1. OOP
      1. Inheritance
      2. R-Value References
    2. Misc Notes
    3. Size/Offsets of Structs/Classes
    4. Week 4
  2. CS200 (IGNORE THIS TOO)
    1. Introduction
    2. Scan Conversion
    3. Quiz 01
  3. GAM200 (YEAH, IGNORE THIS TOO)
    1. Notes

Lesson 1

Bit Manipulations



Value range for various bits


8-bit: 0 - 255
16-bit: 0 - 65,535
32-bit: 0 to 4,294,967,295

For signed values:


8-bit: -128 to 127
16-bit: -32,768 to 32,767
32-bit: -2,147,483,648 to 2,147,483,647

Two's Complement:


2 Steps:
1. Negate every bit in the number (For example, 1 is 0000 0001, so it becomes 1111 1110)
2. Add 1. (So, -1 is 1111 1111)

Note: All negative numbers have the MSB (the one at the front) be 1.

Shifting:


Shifting the integer 7 ONCE to the left yields 14 (7*2 is 14)
0000 0111 << 1 = 0000 1110
Logical Shifting the integer 7 ONCE to the right yields 3 (7/2 = 3.5, so, shifting ROUNDS DOWN. Basically, very similar to integer division)
0000 0111 >> 1 = 0000 0011
Arithmetic Shifting the integer requires the MSB to be duplicated for the introduced bit at the front. This is used for negative sign numbers. (Note that it ROUNDS DOWN, as usual, but in this case just dropping the digits after the dot is not enough, since the number is negative.)
1111 0011 (-13) >> 1 = 1111 1001 = -7

Note: Shifting is the fastest possible operation. It takes one tick (or quantum to complete).
So, let's say you have a clock speed of 3.0 GHz. One G is about 10^9. Hertz is equivalent to cycles per second. That amount of shifts can be done per second by such a CPU.
To put it in perspective, addition takes about 5 ticks, multiplication takes about 10, so with 3.0 GHz, only 0.6G additions and 0.3G multiplications per second can be done.
So basically, instead of multiplying by 2 or a power of 2, use shifting. Similarly, if you are dividing by 2 or a power of 2 and can afford truncuation, use shifting.

Bit Manipulators


Shifting is much more useful when used in conjunction with bitwise operators.
Other bitwise operators are:

& (binary) (AND)
| (binary) (OR)
^ (binary) (XOR)
~ (unary) (one's complement or NOT gate for every bit, basically 0 changes to 1, 1 changes to 0)

Note: OR is a plus, except for when OR'ing 1 and 1 (since the result is 1). AND is always a multiplication.

images\38-1.png

Standard Bit Operations


Note that the letters used aren't chars, they're bits (0 or 1).

Setting a specific bit:

value = value | 1 << BitPosition;
or
value |= (1 << BitPosition);

//Bitshift is higher precedence.


Example:

abcdefgh 
00010000 = 1 << 4
----------- (perform a bitwise “or")
abc1efgh


Explanation:

for any X:
X | 0 = X
So everything along the 0's will just be the same.
for any X:
X | 1 = 1
since:
0 | 1 = 1
1 | 1 = 1


Clearing a specific bit:

value = value & ~ ( 1 << BitPosition);
or
value &= ~ (1 << BitPosition);


Example:
abcdefgh
11101111 = ~(1<<4)
------ perform bitwise “and
abc0efgh


Explanation:
for any X:
X & 1 = X

for any X:
X & 0 = 0


Testing a specific bit:

value & ( 1<< BitPosition );


Example:

abcdefgh
00010000 = 1<<4
--------- perform bitwise “and
000d0000


Explanation:
The result “000d0000” is equal to zero if and only if d is zero.


Memory Efficiency while being an Asshole



Depending on the implementation, you sometimes don't know for sure the size of a boolean (in some cases it may even be the size of an int), so optimization using booleans with that may be useless. But, come on, don't use chars for them to make sure they're a byte. “But I can save a couple byt-” No. That's just, well. No.

Though, of course, you can. In fact, you can do one better (or worse, depending on how you look at it): Since chars are 8 bits each, you can fuck with bitwise operators in order to essentially use each bit as a boolean. But you could also use Dvorak and fuck with your teammates who are trying to help you debug your shit. So no.

Memory Efficiency while not Really being an Asshole


Use bitfields.

int p1: 1;
int p2: 1;
int p3: 1;
...
int p8: 1;


This whole thing will use up 8 bits.
However, you need to know exactly how many bits you need at compile-time. So, y'know, ehhhhh, no (most of the time, at least).

Another example of Memory Effiency Assholery is using 3 bits instead of 4 bits for compass directions. You normally use 4 bits for north, south, east, west, but there's only 8 directions so you could use 3 bits right? Yeah, if you wanna be an asshole and forget down the line what the fuck north-east is.

Basically, if you're going for a race, do you light your ass on fire to go fast? No? Then don't try to be memory efficient if it requires fucking your future self over.

Masks


Masks are basically testing a single bit, like above. Different label, same shit.


value & 0x1//Testing the first bit
value & 0x20//Testing the sixth bit (0010 0000)


Some Useful Notes on Bitwise Operations:


Generally, when using C++, use hexadecimal when working with bitwise stuff. Binary was included in C++14, so you're stuck with decimal (which is shit for bitwise operations), octal and hex.

Bit-wise operators also have distribution properties:
a&c + b&c = (a+b)&c;
This is pretty useful for optimization.

Swapping values with XOR
#define SWAP(a,b) (((a) ^= (b)), ((b) ^= (a)), ((a) ^= (b)))
Note that macros are literally the spawn of satan.

Also, the compiler does a lot of optimization anyway, mostly with constant values.